Posted by Anonymous on Thursday, February 14, 2013 at 12:23pm.
If the near ship is at distance x and the far ship at distance y,
x/80 = cot60°
y/80 = cot45°
The ships are y-x apart.
y-x = 80(1-1/√3) = 33.8m
not very far apart, eh? And both are about ready to crash into the shore!
These ridiculous scenarios bug me. If we're working with such small distances, don't involve ships at sea! Otherwise, say the angles are 12° and 9° or something that will put the ships far away from shore!
thank u so much
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