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March 28, 2015

March 28, 2015

Posted by **Anonymous** on Thursday, February 14, 2013 at 11:24am.

if the line 2x - y +1 = 0 touches the circle at the point (2,5) and the center of the circle lies on the line x+y -9 =0

- maths-urgently needed -
**Steve**, Thursday, February 14, 2013 at 11:36amIf the line touches the circle, then the line from (2,5) to the center is perpendicular to the line y=2x+1, so it has slope -1/2.

So, the line through (2,5) with slope -1/2 is

y-5 = -1/2 (x-2)

y = -1/2 x + 6

This line passes through the center of the circle, so

-1/2 x + 6 = 9-x

x=6

(6,3) is the center of the circle.

The radius is the distance from (6,3) to (2,5) = √20

The circle is thus

(x-6)^2 + (y-3)^2 = 20

Just as a final check:

The distance from (6,3) to the line 2x-y+1 = 0 is |2*6 - 3 + 1|/√5 = 10/√5 = 2√5 = √20

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