Posted by Eve on Thursday, February 14, 2013 at 12:20am.
Use Kepler's third law.
(Period,y)^2/(Distance,a.u.)^3 = 1
(for objects orbiting the sun)
The distance is 7 a.u in this case.
(Period,y)^2 = 7^3 = 343
Period = 18.5 years
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