two point charges are placed on the x axis as follows:

charge q1 = +4.00 nc is located at x = 0.200 m, and charge q2 = +5.00 nc is at x = -0.300 m
what ae the magnitude and direction of the net force exerted by these two charges on a negative point charges q3 = -0.600 nc placed at the origin ?

To find the net force exerted by the two charges on the third charge, we can use Coulomb's Law. Coulomb's Law states that the force between two charges is proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them.

Let's calculate the net force step by step:

Step 1: Find the force between q1 and q3.
The distance between q1 and q3 is the same as the distance between the origin and x = 0.200 m. Let's call it r1.
r1 = 0.200 m

Using Coulomb's Law:
F1 = (k * |q1 * q3|) / r1^2
where k is the Coulomb's constant and |q1 * q3| represents the product of the magnitudes of q1 and q3.

Plugging in the values:
F1 = (9 x 10^9 N*m^2/C^2 * |4.00 x 10^-9 C * -0.600 x 10^-9 C|) / (0.200 m)^2

Calculating:
F1 = (9 x 10^9 N*m^2/C^2 * 2.40 x 10^-18 C^2) / 0.0400 m^2

F1 = 108 x 10^-9 N

Step 2: Find the force between q2 and q3.
The distance between q2 and q3 is the same as the distance between the origin and x = -0.300 m. Let's call it r2.
r2 = 0.300 m

Using Coulomb's Law:
F2 = (k * |q2 * q3|) / r2^2
where |q2 * q3| represents the product of the magnitudes of q2 and q3.

Plugging in the values:
F2 = (9 x 10^9 N*m^2/C^2 * |5.00 x 10^-9 C * -0.600 x 10^-9 C|) / (0.300 m)^2

Calculating:
F2 = (9 x 10^9 N*m^2/C^2 * 3.00 x 10^-18 C^2) / 0.0900 m^2

F2 = 270 x 10^-9 N

Step 3: Find the net force.
The net force is the vector sum of the forces F1 and F2. Since they act in opposite directions, we need to subtract the magnitudes.
Net Force = |F1 - F2|

Calculating:
Net Force = |108 x 10^-9 N - 270 x 10^-9 N|
Net Force = 162 x 10^-9 N

Therefore, the magnitude of the net force exerted by the two charges on the third charge is 162 x 10^-9 N.

In terms of direction, we can determine that the net force is directed towards the positive x-axis because q1 and q3 are both positive charges, while q2 is a negative charge.

To calculate the net force exerted by these two charges on the negative point charge at the origin, you can use Coulomb's Law.

Coulomb's Law states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them. The formula for the force is given by:

F = (k * |q1 * q3|) / r^2

where F is the net force, k is the electrostatic constant (9 x 10^9 N*m^2/C^2), |q1| and |q3| are the magnitudes of the charges, and r is the distance between the charges.

Let's calculate the net force step by step:

1. Calculate the distance between the negative point charge at the origin and each of the other charges.
- Distance between q3 and q1 (r1) = x1 = 0.200 m
- Distance between q3 and q2 (r2) = x2 = -0.300 m

2. Calculate the net force exerted by each charge on q3:
- Force between q1 and q3 (F1) = (k * |q1 * q3|) / r1^2
- Force between q2 and q3 (F2) = (k * |q2 * q3|) / r2^2

3. Add the forces to find the net force exerted on q3:
Net force (F_net) = F1 + F2

4. Determine the magnitude and direction of the net force. The magnitude is given by |F_net|, and the direction is determined by the sign of the charges and the direction of the forces.

Now let's substitute the given values into the formulas and calculate the magnitude and direction of the net force.

draw the diagram. Notice the charge to the left attracts the q3, to the left. Now notice the q1 pulls toward the right.

Figure the forces due to q1q3, and q2q3, which are are in opposite directions. The resultant force will be in thedirection of the larger.

Answer