Help Please!!!!
H2SO4(aq) = 2H+(aq) + SO42-(aq)
What is the hydrogen ion concentration, in mol dm−3, when 1.50 g of sulfuric acid is dissolved in water to give 0.500 dm3 of solution
molarityH+= 2*(1.50/molmassH2SO4)/.5
To find the hydrogen ion concentration in mol dm^−3, we need to use the molar mass of sulfuric acid and the volume of the solution.
First, calculate the number of moles of sulfuric acid in 1.50 g using the equation:
number of moles = mass / molar mass
The molar mass of sulfuric acid (H2SO4) is:
(2 x atomic mass of hydrogen) + atomic mass of sulfur + (4 x atomic mass of oxygen)
= (2 x 1.01 g/mol) + 32.07 g/mol + (4 x 16.00 g/mol)
= 98.09 g/mol
Now we can calculate the number of moles of sulfuric acid:
number of moles = 1.50 g / 98.09 g/mol = 0.0153 mol
Next, we convert the volume of the solution from dm^3 to liters:
Volume = 0.500 dm^3 = 0.500 L
Finally, we divide the number of moles of sulfuric acid by the volume of the solution to find the hydrogen ion concentration:
Hydrogen ion concentration (mol dm^-3) = number of moles / volume
= 0.0153 mol / 0.500 L
= 0.0306 mol dm^-3
Therefore, the hydrogen ion concentration in the solution is 0.0306 mol dm^-3.