Post a New Question
posted by Lost One Wednesday, February 13, 2013 at 2:15pm.
Find the area of the region bound by f(y) = 9y - y^2 and the y-axis over the interval 3 <= y <= 6.
what's the trouble? pretty straightforward integration ∫[3,6] 9y - y^2 dy = 9/2 y^2 - 1/3 y^3 [3,6] = 117/2
More Related Questions