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December 19, 2014

December 19, 2014

Posted by **sherika** on Wednesday, February 13, 2013 at 1:46pm.

- math -
**Lena**, Wednesday, February 13, 2013 at 2:20pmOK. So let's create a formula of some sort. So what do we know?

- When we remove 15 L from 2/3 filled drum, we have only 3/5 of the drum full

Let's change this to a mathematical sentence.

Let's say that whole drum holds 'x' Litres

So we can say the following:

2/3 x - 15 = 3/5 x

(So 2/3 of the total volume of the drum minus 15 L is equal to 3/5 of the total volume of the drum)

2/3 x - 3/5 x = 15

1/15 x = 15

x = 15 * 15

x = 225 L

So the capacity of the drum should be 225 L.

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