Monday

November 24, 2014

November 24, 2014

Posted by **KUMAR** on Wednesday, February 13, 2013 at 12:56pm.

- MATH -
**Balaji**, Saturday, February 16, 2013 at 10:58amJoin the centers of the 3 triangles to form an equilateral triangle with sides length 20.

The area enclosed by the 3 triangles will be the area of this triangle minus the area

of 3 sectors of the circles with central angles of 60 degrees. Thus the area of the

enclosed region will be

(1/2)*(20)*(20*sin(60)) - 3*(60/360)*pi*10^2 =

200*(sqrt(3) /2) - 50*pi = 100*sqrt(3) - 50*pi.

So a + b + c = 100 + 3 + 50 = 153.

**Answer this Question**

**Related Questions**

maths - Three circles, each with a radius of 10, are mutually tangent to each ...

geometry!!!!!!!!!! - Three circles, each with a radius of 10, are mutually ...

maths - Three circles, each with a radius of 10, are mutually tangent to each ...

geometry - Three circles, each with a radius of 10, are mutually tangent to each...

PLEASE HELP TANGENTS AND CIRCLES PROBLEM GEOMETRY - PLEASE HELP I REALLY NEED ...

geometry - Three circles are externally tangent to one another. The radius of ...

Math. I really don't get this question - three circles are manually tangent ...

GEOMETRY(CIRCLE) - Three circles with different radii have their centers on a ...

geometry - Each of the three circles have a radius of 10. The line OA contains ...

maths - there are two circles touching each other at one point. The radius of ...