Posted by m on Wednesday, February 13, 2013 at 8:30am.
First you want to calculate the (HCl). That's
density x 1000 mL x (%/100) x 1/molar mass = M
1.179 x 1000 x 0.36 x (1/36.5) =11.6 M
Then c1v1 = c2v2
What H^+ do you want for pH = 1.8? That is 1.8 = -log(H^+) = about 0.0158
c = concn
v = volume
11.6 x v = 0.0158 x 4,700 mL
v = ? mL.
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