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September 30, 2014

September 30, 2014

Posted by **kikii** on Wednesday, February 13, 2013 at 2:23am.

y=log to the base 10 (2x+3/x-5)

pleaseee need to understand before the test tmr!!!!

No one has answered this question yet.

- pre calc -
**Steve**, Wednesday, February 13, 2013 at 12:59pmIf your log is of (2x+3)/(x-5), then you must have

(2x+3)/(x-5) > 0

So, either both are positive or both are negative, so the domain is

x < -3/2 or x > 5

As x -> ∞, y->log2

For x < -3/2, y < log2

For x > 5, y > log2

The range is all reals except y=log2

That is the horizontal asymptote

The vertical asymptotes are at x = -3/2, 5

For the y-intercept, what is y when x=0?

Well, log(-3/5) is not defined, so there is no y-intercept

When is y=0? When (2x+3)/(x-5) = 1

That is, x = -8

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