pre calc
posted by kikii .
how do uu find the x int. , y int. , domain range asytote of this equation
y=log to the base 10 (2x+3/x5)
pleaseee need to understand before the test tmr!!!!
No one has answered this question yet.

If your log is of (2x+3)/(x5), then you must have
(2x+3)/(x5) > 0
So, either both are positive or both are negative, so the domain is
x < 3/2 or x > 5
As x > ∞, y>log2
For x < 3/2, y < log2
For x > 5, y > log2
The range is all reals except y=log2
That is the horizontal asymptote
The vertical asymptotes are at x = 3/2, 5
For the yintercept, what is y when x=0?
Well, log(3/5) is not defined, so there is no yintercept
When is y=0? When (2x+3)/(x5) = 1
That is, x = 8