Post a New Question

pre calc

posted by .

how do uu find the x int. , y int. , domain range asytote of this equation

y=log to the base 10 (2x+3/x-5)

pleaseee need to understand before the test tmr!!!!

No one has answered this question yet.

  • pre calc -

    If your log is of (2x+3)/(x-5), then you must have

    (2x+3)/(x-5) > 0
    So, either both are positive or both are negative, so the domain is

    x < -3/2 or x > 5

    As x -> ∞, y->log2
    For x < -3/2, y < log2
    For x > 5, y > log2
    The range is all reals except y=log2

    That is the horizontal asymptote
    The vertical asymptotes are at x = -3/2, 5

    For the y-intercept, what is y when x=0?
    Well, log(-3/5) is not defined, so there is no y-intercept

    When is y=0? When (2x+3)/(x-5) = 1
    That is, x = -8

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question