Posted by **Vivi** on Wednesday, February 13, 2013 at 1:59am.

Car A traveling southward towards Point P at 45 mi/hr. Car B is traveling east away from P at 30mi/hr. AT the instant when the distance AP is 60 mi and PB is 80 mi, what is the rate of change of distance AB?

- Calculus -
**Steve**, Wednesday, February 13, 2013 at 1:04pm
We have a nice 3-4-5 triangle at the moment in question, so AB = 100

If we let x and y be the distances of the two cars (B and A) then the distance d=AB is

d^2 = x^2 + y^2

2d dd/dt = 2x dx/dt + 2y dy/dt

so, when x=80 and y=60, d=100, and we have

100 dd/dt = 80(30) + 60(-45)

dd/dt = -3

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