Posted by **Kat** on Wednesday, February 13, 2013 at 12:51am.

Is it possible to construct a rectangle whose length is 1cm less than twice its width, and whose area is 40cm^2? If your answer is yes, determine the dimensions of the rectangle to the nearest tenth of a centimetre. If your answer is no, explain why it is not possible.

I know it's possible, but I don't know how to get the answer. Please help me! My test is tomorrow. ><

Thanks!

## Answer This Question

## Related Questions

- math - the length of a rectangle is 1 cm less than twice its width. the area is ...
- math - a rectangle is twice as long as it is wide. if both of its dimensions are...
- math - The length of a rectangle is twice the width. If the length is increased ...
- alegbra1 - The length of a rectangle is twice the width. If the length is ...
- Algebra - The length of a rectangle is 1 foot less than twice the width, and the...
- Algebra - The area of a rectangle is 21 ft^2,and the length of the rectangle is ...
- algebra - A wire is 264 ft in length is to be cut into two pieces, one to form a...
- algebra - The length of a rectangle is 3 more than twice the width. The area of ...
- Algebra/geometry - a rectangle has a width of 4 cm less than it's length. if a ...
- math - the length of a rectangle is 3 yds more than twice it width and the area ...

More Related Questions