precal
posted by Argelia .
solve for all values in [0,2pie)
2sin^2x1=0

2sin^2x1=0
sin^2 x = 1/2
sinx = ±1/√2
I know sin 45° = 1/√2 or sin π/4 = 1/√2
because of the ± , our angle could be in any of the 4 quadrants
so x = π/4 , 3π/4, 5π/4 , 7π/4