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March 28, 2017

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solve for all values in [0,2pie)
2sin^2x-1=0

  • pre-cal - ,

    2sin^2x-1=0
    sin^2 x = 1/2
    sinx = ±1/√2

    I know sin 45° = 1/√2 or sin π/4 = 1/√2

    because of the ± , our angle could be in any of the 4 quadrants
    so x = π/4 , 3π/4, 5π/4 , 7π/4

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