Posted by Argelia on Tuesday, February 12, 2013 at 10:52pm.
solve for all values in [0,2pie)
2sin^2x1=0

precal  Reiny, Wednesday, February 13, 2013 at 12:03am
2sin^2x1=0
sin^2 x = 1/2
sinx = ±1/√2
I know sin 45° = 1/√2 or sin π/4 = 1/√2
because of the ± , our angle could be in any of the 4 quadrants
so x = π/4 , 3π/4, 5π/4 , 7π/4
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