Posted by **Argelia** on Tuesday, February 12, 2013 at 10:52pm.

solve for all values in [0,2pie)

2sin^2x-1=0

- pre-cal -
**Reiny**, Wednesday, February 13, 2013 at 12:03am
2sin^2x-1=0

sin^2 x = 1/2

sinx = ±1/√2

I know sin 45° = 1/√2 or sin π/4 = 1/√2

because of the ± , our angle could be in any of the 4 quadrants

so x = π/4 , 3π/4, 5π/4 , 7π/4

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