Posted by Sarah on .
Determine the equation of a line that passes through (2,2) and is parallel to the line tangent to y=3x^3-2x at (-1,5)?
slope of y=3x^3-2x is 9x^2-2
so, slope at (-1,5) is 7
so, now yu have a point and a slope:
y-2 = 7(x-2)