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Determine the equation of a line that passes through (2,2) and is parallel to the line tangent to y=3x^3-2x at (-1,5)?

  • Pre-Calculus - ,

    slope of y=3x^3-2x is 9x^2-2
    so, slope at (-1,5) is 7

    so, now yu have a point and a slope:

    y-2 = 7(x-2)

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