Posted by Becky on .
Find the derivative of m(x)=1/(x+1) by using the definition of the derivative.

Calculus 
Steve,
we want the limit as h>0 of
[m(x+h)m(x)]/h
= [1/(x+1+h)  1/(x+1)]/h
= [(x+1)  (x+1+h)] / h(x+1)(x+1+h)
= h/h * 1/(x+1)(x+1+h)
> 1/(x+1)^2