Saturday

April 19, 2014

April 19, 2014

Posted by **Becky** on Tuesday, February 12, 2013 at 9:00pm.

- Calculus -
**Steve**, Tuesday, February 12, 2013 at 11:13pmwe want the limit as h->0 of

[m(x+h)-m(x)]/h

= [1/(x+1+h) - 1/(x+1)]/h

= [(x+1) - (x+1+h)] / h(x+1)(x+1+h)

= h/h * -1/(x+1)(x+1+h)

--> -1/(x+1)^2

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