Post a New Question

Calculus

posted by on .

Solve for x in the equation ln(16-12x)-2lnx)= ln4

  • Calculus - ,

    ln [ (16-12x)/x^2 ] = ln 4
    (16-12x)/x^2 = 4
    4x^2 = 16-12x
    x^2 + 3x - 4 = 0
    (x+4)(x-1) = 0
    x = -4 or x=1

    but if x = -4 , 2lnx in the original equation is not defined, so

    x = 1

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question