Calculus
posted by Emily on .
Solve for x in the equation ln(1612x)2lnx)= ln4

ln [ (1612x)/x^2 ] = ln 4
(1612x)/x^2 = 4
4x^2 = 1612x
x^2 + 3x  4 = 0
(x+4)(x1) = 0
x = 4 or x=1
but if x = 4 , 2lnx in the original equation is not defined, so
x = 1