Which are enatiomers? optically active?identical? diastereomers?

A.)...CH3
.....|
...H-C-Cl
.....|
.....Ch2Cl

B.).....H
.......|
...H3C-C-CH2CL
.......|
.......CL

C.)...CH3
.......|
....CL-C-H
......|
......CH2CL

D.)....CH2CL
.........|
......CL-C-H
.........|
.........CH3

E.).....CH3
........|
......H-C-CL
........|
......H-C-CL
........|
........CH3

F.).....CH3
........|
.....CL-C-H
........|
.....CL-C-H
........|
........CH3

G.)...CH3
......|
....H-C-CL
......|
...CL-C-H
......|
......CH3

H.)....CH3
........|
.....CL-C-CL
........|
......H-C-H
........|
........CH3

Thank you :)

Enantiomers are stereoisomers that are non-superimposable mirror images of each other. They have the same molecular formula and connectivity, but differ in the spatial arrangement of atoms. To determine if a molecule is an enantiomer, we need to examine its stereochemistry.

In each given structure, we can identify the chiral centers, which are carbon atoms bonded to four different groups. Let's analyze each structure and determine if they are enantiomers, optically active, identical, or diastereomers:

A) This molecule has a chiral center (the central carbon bonded to H, Cl, CH3, and Ch2Cl). To determine its enantiomer, we need to create a mirror image. However, the mirror image of A is identical to A itself, indicating that A is not an enantiomer.

B) Like structure A, B also has a chiral center. Creating a mirror image results in a different molecule, indicating that B is an enantiomer.

C) This molecule lacks a chiral center since the carbon bonded to the two chlorine atoms is not bonded to four different groups. Therefore, C cannot be an enantiomer.

D) Similar to C, this molecule lacks a chiral center and cannot be an enantiomer.

E) This molecule has two chiral centers. You can create a mirror image by swapping the positions of the two CH3 groups. The mirror image and the original molecule are different, indicating that E is an enantiomer.

F) Similar to E, F also has two chiral centers. Exchanging the positions of the CH3 groups results in a different molecule, indicating that F is an enantiomer.

G) This molecule has a chiral center, but it also has a meso compound. A meso compound has chiral centers but is not optically active due to internal symmetry. Therefore, G is not an enantiomer but is optically inactive.

H) Similar to G, H also has a chiral center and a meso compound, making it optically inactive but not an enantiomer.

To summarize:
- Enantiomers: B, E, F
- Optically active (non-enantiomers): None
- Identical: None
- Diastereomers: All pairs that are not enantiomers (A, C, D, G, H)

Note: In this analysis, we only considered the stereochemistry based on the given structural formulas. The actual names and descriptions of the compounds might differ depending on the conventions used in organic chemistry.

Enantiomers:

Enantiomers are pairs of molecules that are non-superimposable mirror images of each other. In other words, they have the same chemical formula and connectivity, but their spatial arrangement is different, resulting in different optical properties. Enantiomers rotate plane-polarized light in opposite directions.

Optically active:
A compound is considered optically active if it has the ability to rotate the plane of polarized light. Enantiomers are optically active because they rotate light in opposite directions.

Identical:
In chemistry, two molecules are considered identical if they have the same chemical formula and connectivity. They are similar in all aspects, including their physical and chemical properties.

Diastereomers:
Diastereomers are stereoisomers that are not mirror images of each other. Unlike enantiomers, diastereomers do not have identical physical and chemical properties. They have different arrangements of atoms in their structures.

Now, let's examine the given compounds in relation to these terms:

A.) This compound appears to have a chiral carbon atom, but it also contains an internal plane of symmetry. Therefore, it is not chiral and does not have enantiomers.

B.) This compound also appears to have a chiral carbon atom, and it lacks any internal plane of symmetry. Therefore, it is chiral and can have enantiomers.

C.) This compound does not have a chiral carbon atom since it has two chlorine atoms attached to it. Therefore, it is not chiral and does not have enantiomers.

D.) Similar to compound C, this compound does not have a chiral carbon atom. Therefore, it is not chiral and does not have enantiomers.

E.) This compound appears to have two chiral carbon atoms, and it lacks any internal plane of symmetry. Therefore, it is chiral and can have enantiomers.

F.) This compound does not have a chiral carbon atom since it has two chlorine atoms attached to it. Therefore, it is not chiral and does not have enantiomers.

G.) Similar to compound F, this compound does not have a chiral carbon atom. Therefore, it is not chiral and does not have enantiomers.

H.) This compound appears to have a chiral carbon atom, but it also contains an internal plane of symmetry. Therefore, it is not chiral and does not have enantiomers.

To summarize, compounds B and E are chiral and can have enantiomers, whereas compounds A, C, D, F, G, and H are not chiral and do not have enantiomers.