Posted by Cassie on .
Acetic acid ionizes in water as follows:
CH3COOH + H2O CH3COO– + H3O+
Fewer than 1% of ethanoic acid molecules are ionized at any instant. The acetate ion (CH3COO– ) is therefore ____.
A.a poor hydrogen-ion acceptor
B.a good hydrogen-ion acceptor
C.a poor hydrogen-ion donor
D.a good hydrogen-ion donor
I posted this question ealier and have reread some information and I am getting 2 answers between B and C?
Can anyone clarify? Thank you in advance...
Okay, I didn't read the question correctly/carefully. I thought the question was asking about acetic acid, not the ion; I apologize about that. Acetic acid is a weak acid, and thus a poor hydrogen ion donor. Its conjugate base, the acetate ion, would be a good hydrogen-ion acceptor.
Correction, it would be a poor hydrogen-ion acceptor.
Google: wisconsin acid and base conjugates
Take a look at wisconsin's website to understand what the correct answer will be.
A is the correct answer.
A is NOT the correct answer, i just took this test and it is...
Fewer than 1% of ethanoic acid molecules are ionized at any instant. The acetate ion (CH3COO– ) is therefore ____. (1 point)
(0 pts) a poor hydrogen-ion acceptor
(1 pt) a good hydrogen-ion acceptor
(0 pts) a poor hydrogen-ion donor
(0 pts) a good hydrogen-ion donor