posted by Anonymous .
What volume of 0.1 M NaOH is required to neutralize 30 mL of 0.1 M HCl?
Calculate the number of moles for HCl in a 30mL sample of 0.1M HCl
30 x10^-3 L*(0.1M)=moles of HCl
The number of moles of HCl/the molarity of NaOH will give you the volume needed in L.
volume in L=moles of HCl/0.1 M NaOH
*** Multiply the volume by 10^3 if you need to report the volume in mLs.