Posted by john on Monday, February 11, 2013 at 11:25pm.
If the distance of A is d, and the building's height is h,
(h-8.2)/d = tan 31°20'
8.2/d = tan 12°50'
so, equating d,
(h-8.2)/tan 31°20' = 8.2/tan 12°50'
(h-8.2)/.6088 = 8.2/.2278
h = 30.11 m
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