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November 29, 2014

November 29, 2014

Posted by **john** on Monday, February 11, 2013 at 11:25pm.

- Pre cal -
**Steve**, Tuesday, February 12, 2013 at 12:22amIf the distance of A is d, and the building's height is h,

(h-8.2)/d = tan 31°20'

8.2/d = tan 12°50'

so, equating d,

(h-8.2)/tan 31°20' = 8.2/tan 12°50'

(h-8.2)/.6088 = 8.2/.2278

h = 30.11 m

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