Posted by HELP !!!! on Monday, February 11, 2013 at 11:08pm.
The current when it "just begins to turn the blade" is a starting surge current. There is no back emf (Vb) at that time. Let R be the resistance of the motor coils.
The starting surge current is 120V/R.
The current at normal operating speed is (120 - Vb)/R
(120 - Vb)/R = 0.109*(120/R)
Vb = 120 - 13.08 = 106.9 V
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