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Calculus

posted by on .

Find the derivatives of the function
k(x)=sqrt(sin(2x))^3

I think I have the answer and was wondering if i had it correct
k'(x)=2sin(x)^3+8sin(x)

  • Calculus - ,

    I will interpret your question just the way you typed it

    k(x) = √ [ (sin(2x) )^3 ] which is
    = ( sin(2x) )^(3/2)

    k ' (x) = (3/2)( sin(2x))^(1/2) ( cos(2x)) (2)
    = 3 cos(2x) √(sin(2x))

  • Calculus - ,

    ok thank you

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