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Applied Calculus

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Find the derivative of the function:

f(x)=(x^2+9)/square roote of x

  • Applied Calculus - ,

    f(x)=u/v

    f'=u'/v -v'u/v^2

    can you do that? u=x^2+9 v=x^.5
    u'=2x v'=1/2 x^-.5

  • Applied Calculus - ,

    Yeah, what I accidently did was I tried to solve it further, but I completely over thought that. Thank you Bob!

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