Wednesday

November 26, 2014

November 26, 2014

Posted by **Jacob** on Monday, February 11, 2013 at 9:50pm.

f(x)=(x^2+9)/square roote of x

- Applied Calculus -
**bobpursley**, Monday, February 11, 2013 at 10:02pmf(x)=u/v

f'=u'/v -v'u/v^2

can you do that? u=x^2+9 v=x^.5

u'=2x v'=1/2 x^-.5

- Applied Calculus -
**Jacob**, Monday, February 11, 2013 at 10:09pmYeah, what I accidently did was I tried to solve it further, but I completely over thought that. Thank you Bob!

**Answer this Question**

**Related Questions**

Applied Calculus - Find the third derivative of the function: g(t)=square root ...

Applied Calculus - Find the third derivative of the function: g(t)=square root ...

Applied Calculus - Find the first and second derivative of the function: x/(7x+...

Applied Calculus - Find the derivative of the function: (x^(3)-8)/(x^(2)+9)

Applied Calculus - Find the third derivative of the function: (5t+4)^(1/2)

Calculus - Any help would be much appreciated with the steps involved in each ...

Calculus - Any help would be much appreciated with the steps involved in each ...

Applied Calculus - Find the derivative of this function: g(t)=(8t+10)^2*(10t^2-7...

Applied Calculus - Find the derivative of the function f by using the rules of ...

Calculus - Find the derivative of the function y=x2 + 2x + 1/ square root of x2...