Post a New Question


posted by on .

As a hot-air balloon rises vertically, its angle of elevation from a point P on level ground d = 140 kilometers from the point Q directly underneath the balloon changes from 15°10' to 29°30' (see the figure). Approximately how far does the balloon rise during this period? (Give the answer to one decimal place.)

  • trig - ,

    For height at lower angle:
    tan 15°10' = height1/140
    height1 = 140tan15°10'

    in the same way:
    height2 = 140tan29°30'

    rise of the balloon in that change of angle
    = 140tan29°30' - 140tan15°10'
    = 41.256

    I am sure your units are not correct.
    How can they even see the balloon from 140 km away ?

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question