Posted by
**Jenny** on
.

Determine the convergence or divergence of the series. Indicate the test that was used and justify your answer.

Sigma (lower index n = 1; upper index infinity) [(-1)^n*3^n]/(n*2^n)

Tuesday

March 28, 2017
Posted by
**Jenny** on
.

Determine the convergence or divergence of the series. Indicate the test that was used and justify your answer.

Sigma (lower index n = 1; upper index infinity) [(-1)^n*3^n]/(n*2^n)

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