# Calculus

posted by
**Jenny** on
.

Determine the convergence or divergence of the series. Indicate the test that was used and justify your answer.

Sigma (lower index n = 1; upper index infinity) [(-1)^n*3^n]/(n*2^n)

posted by
**Jenny** on
.

Determine the convergence or divergence of the series. Indicate the test that was used and justify your answer.

Sigma (lower index n = 1; upper index infinity) [(-1)^n*3^n]/(n*2^n)