Wednesday

April 16, 2014

April 16, 2014

Posted by **Jenny** on Monday, February 11, 2013 at 6:08pm.

Sigma (lower index n = 1; upper index infinity) 4^n/(3^n-1)

- Calculus -
**Steve**, Monday, February 11, 2013 at 6:16pmHow about showing us some of your thoughts? So many posts look like homework dumping.

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