Sunday

February 1, 2015

February 1, 2015

Posted by **Jenny** on Monday, February 11, 2013 at 6:08pm.

Sigma (lower index n = 1; upper index infinity) 4^n/(3^n-1)

- Calculus -
**Steve**, Monday, February 11, 2013 at 6:16pmHow about showing us some of your thoughts? So many posts look like homework dumping.

**Answer this Question**

**Related Questions**

Calculus - Determine the convergence or divergence of the series. Indicate the ...

Calculus - Determine the convergence or divergence of the series. Find the limit...

Calculus - Test for convergence or divergence. Indicate the test that was used ...

Calculus - Test for convergence or divergence. Indicate the test that was used ...

Calculus - Determine the following about the series. Indicate the test that was ...

calculus - Consider ∞ ∑ [(3k+5)/(kČ-2k)]ᵖ, for each p ∈...

calculus - test the series for convergence or divergence the series from n=0 to ...

calculus - test the series for convergence or divergence the series from n=0 to ...

calculus - test the series for convergence or divergence the series from n=1 to ...

calculus - in the following series x is a real number. In each case use the ...