Test for convergence or divergence. Indicate the test that was used and justify your answer.
Sigma (lower index n = 4; upper index infinity) 1/(3n^2-2n-15)
3n^2-2n-15 > n^2 for n>=4,
the series converges since 1/n^2 converges
Sigma (lower index n = 4; upper index infinity) 1/(3n^2-2n-15)
the series converges since 1/n^2 converges