Posted by **Jenny** on Monday, February 11, 2013 at 6:06pm.

Determine the following about the series. Indicate the test that was used and justify your answer.

Sigma (lower index n = 1; upper index infinity) [sin((2n-1)pi/2)]/n

A. The series diverges

B. The series converges conditionally.

C. The series converges absolutely.

D. It cannot be determined.

## Answer This Question

## Related Questions

- Calculus - Determine the convergence or divergence of the series. Indicate the ...
- Calculus - Determine the convergence or divergence of the series. Find the limit...
- Calculus - Find the values of x for which the series converges. Sigma (lower ...
- Calculus - The problem with these two questions is that I cannot determine the a...
- Calculus - Use the Direct Comparison Test to determine the convergence or ...
- calculus - determine whether the series converges of diverges the sum from n=1 ...
- calculus - determine whether the series converges of diverges the sum from n=1 ...
- calculus - determine whether the series converges of diverges the sum from k=2 ...
- calculus - determine whether the series converges of diverges the sum from k=2 ...
- Calc - Does 1/ln(x+1) converge or diverge? I've tried the nth term test, limit ...

More Related Questions