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April 24, 2014

April 24, 2014

Posted by **Jenny** on Monday, February 11, 2013 at 6:05pm.

Sigma (lower index n = 1; upper index infinity) 12/[n(n+3)]

- Calculus -
**Steve**, Monday, February 11, 2013 at 6:10pmwe know that sum 1/n^2 = pi/6

Since n(n+3) > n^2, it also converges

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