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1. Given the following equation:
Glycerol-3-phosphate glycerol + Pi Go’ = -9.7 kJ/mol
At equilibrium the concentrations of both glycerol and inorganic phosphate are 1 mM. Under these conditions, calculate the final concentration of glycerol-3-phosphate. Remember to convert kJ to J.

2. Using the data for the reaction in question 1, calculate the G value (Go’ = -13.8 kJ/mol).

  • Biochemistry -

    I'm not sure if you typed in the reaction correctly. If the reaction is as followed:

    Glycerol-3-phosphate----> Glycerol + Pi
    ∆G0'= -9.7kj

    Then this what you I believe you should do:

    The removal of the phosphate is the only way that I can see the reaction being energetically favorable, and at equilibrium, ∆G =0.

    R=0.0083145 kJ/mol
    ∆Go'= -9.7kj/mol
    Glycerol= 1mM

    Plug in your values and solve for Glycerol 3-phosphate








    [1mM][1mM]/(9.7kj/mol)/[(0.0083145 kJ/mol)(298.15K)]=G3P

    For the second part, use the value that you obtained for G3P, and the values that are given to you for Glycerol, ∆G0' (-13.8 kJ/mol), and Pi and plug into
    the equation below and solve.


  • Biochemistry -

    Last part of the equation for the first step should be,

    [1mM][1mM]/10^[(9.7kj/mol)/[(0.0083145 kJ/mol)(298.15K)]=G3P

  • Biochemistry -

    I have a bad typo in my original post that may lead to confusion: replace the words reactants with products and vis versa. Everything else is okay except for that.

  • Biochemistry -

    Meaning, Q=products/reactants, not the other way around. for 10^(-∆G0'/RT)=Reactants/Products part of the equation manipulation.

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