Posted by Angela on Monday, February 11, 2013 at 10:45am.
I'm not sure if you typed in the reaction correctly. If the reaction is as followed:
Glycerol-3-phosphate----> Glycerol + Pi
Then this what you I believe you should do:
The removal of the phosphate is the only way that I can see the reaction being energetically favorable, and at equilibrium, ∆G =0.
Plug in your values and solve for Glycerol 3-phosphate
For the second part, use the value that you obtained for G3P, and the values that are given to you for Glycerol, ∆G0' (-13.8 kJ/mol), and Pi and plug into
the equation below and solve.
Last part of the equation for the first step should be,
I have a bad typo in my original post that may lead to confusion: replace the words reactants with products and vis versa. Everything else is okay except for that.
Meaning, Q=products/reactants, not the other way around. for 10^(-∆G0'/RT)=Reactants/Products part of the equation manipulation.
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