the specific heat of granite is 0.80 KJ/kg . c. I f 1.6 MJ of heat are added to a 100-kg granite statue of James Precott Joule that is originally at 18 C, what is the finale temperature of the statue
To find the final temperature of the granite statue, we can use the formula:
Q = mcΔT
Where:
Q is the heat added (in joules),
m is the mass of the granite (in kilograms),
c is the specific heat capacity of granite (in joules per kilogram per degree Celsius),
ΔT is the change in temperature (in degrees Celsius).
First, let's convert the specific heat capacity from kilojoules to joules:
0.80 KJ/kg . c = 0.80 * 1000 J/kg . c = 800 J/kg . c
Now, we can rearrange the formula to solve for ΔT:
ΔT = Q / (mc)
Given:
Q = 1.6 MJ = 1.6 * 10^6 J
m = 100 kg
c = 800 J/kg . c
Plugging in the values, we get:
ΔT = (1.6 * 10^6 J) / (100 kg * 800 J/kg . c)
ΔT = 20 degrees Celsius
Therefore, the final temperature of the granite statue will be:
Final temperature = Initial temperature + ΔT
Final temperature = 18 C + 20 C
Final temperature = 38 degrees Celsius