Posted by **ujjval** on Monday, February 11, 2013 at 10:00am.

Q:20

A clock was 4

minutes slow at noon on Friday and 4 minutes 36 seconds fast on

the following Friday at 4 P.M. If the clock gains uniformly, when

does it show the correct time?

A:8 P.M. on Monday (after

second Friday)

B:8 P.M. on Monday

(between two Fridays)

C:10 P.M. on Monday

(after second Friday)

D:8 A.M. on Monday

(between two Fridays)

- maths -
**Steve**, Monday, February 11, 2013 at 3:15pm
time elapsed was 7 days + 4 hours = 619200 seconds

during that time the amount the clock was off went from -240 to +276, so it gained 516 seconds.

So, if it was right on after x seconds, then

-240 + 516n/619200 = 0

x = 288000 seconds = 3 days 8:00:00

so, (B)

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