Posted by Ashley on Sunday, February 10, 2013 at 11:47pm.
If we call the (H2CO3) = 0.034M, then
...........H2CO3 ==> H^+ + HCO3^-
I..........0.034......0......0
C..........-x.........x......x
E..........0.034-x.....x.....x
Substitute the E line into k1 for H2CO3 (look that up in your text tables) and solve for x = (H^+) then convert to pH.
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