Sunday

April 20, 2014

April 20, 2014

Posted by **Calculus** on Sunday, February 10, 2013 at 11:31pm.

First choose the interval of length .1 with 3 being the left endpoint of

the interval.

Then f'(3)≈ ______

Now let the interval have length .01. Then f'(3)≈ _______

Finally let the interval have length .001

Then f'(3)≈

**I am genuinely lost on where to even begin with this problem. I understood the rest of my homework completely, except this one. My homework will be due before someone can get to answer this, I am almost sure of that, so please - just work it out for me so that I can better understand it for the midterm.

**Related Questions**

algebra1/McDougal Littell - I need to know how to work this problem and show my ...

calculus - f''(x) = (3x^3 - 5x^2 + 1) / x^2; and f(1) = 0, f(-1) = 1. So i turn ...

Math - Can someone please check my answers below for accurateness? The ...

Algebra 2 - The problem is 3x^2 - 26 + 35 (We have to factor it!) So, I did the ...

calculus derivatives - Please confirm: {(5x+2)^4/x^2-3x+1)^3}= 20(5x+2)^2(x^2-3x...

Calculus derivative - Find the slope and an equation of the tangent line to the ...

math, beginning algebra - how do i solve the following equations. Problem # 1 3x...

Math - AlgebrAic factorization 1)6(2a-3)(a+7)+18(2a-3)(3a+2) 2) (3x-4)(5x+1)-(...

math - Logarithm 3^3x+1=3^5x-2 3^3x+1-3^5x-2=0 Log(3^3x+1-3^5x-2)=log0 Please ...

Algebra - For each equarion, write the equivalent equation that expresses y in ...