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math 7

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if you have 8 marbles in the bag (5 blue and 3 green) and you draw 2 with replacement, what is the theoretical probability that both marbles wil be green
how does the probability of getting two greens change if you are not replacing??

if you have 8 marbles in the bag (5 blue and 3 green) and you draw 2 without replacement, what is the theoretical probability that both marbles will be green

if you have 8 marbles in the bag (5 blue and 3 green) and you draw 2 with replacement, what is the theoretical probability that both marbles will be green

  • math 7 -

    idk
    11% without
    39% with

  • math 7 -

    with replacement:
    prob(2 green) = (3/8)(3/8) = 9/64

    without replacement
    prob(2 green) = (3/8)(2/7) = 6/56 = 3/28

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