Homework Help: math

Posted by alicia on Sunday, February 10, 2013 at 10:21pm.

If the digits of a number may be any one of 0 through 9 (except the first digit cannot be zero), and the system of alternating signs of coefficients is used to create a polynomial, what is the least number m of real zeros the polynomial can have? What is the greatest number M of real zeros it may have? Can a polynomial of this type have any whole number of real zeros between m and M? Why or why not?

No one has answered this question yet.

Answer this Question

Related Questions

math - Find a six-digit even number containing no zeros and no repeating digits ...
math - Using the numbers 1 through 9 with no repeats, find a 9 number such that...
Math - i am a four digit number. all of my digits are different. my first digit ...
math - What mystery number has 8 digits; none of the digits are the same. It is ...
math - *The number has 8 digits, none of the digits are the same. *It is evenly ...
math - The number has 8 digits none of the digits are the same 2. It is enemy ...
Math - A number has four digits. the sum of the first and last digits is twice ...
math - 1. a door code is made up of six unique digits the last digit is 8. 2....
Math - The mystery number's tens digit is less than the ones digit. The tens...
Math - A number has 4 digits. The sum of the first and last digit is twice the ...

For Further Reading

First Name:
School Subject:
Answer: