Posted by **alicia** on Sunday, February 10, 2013 at 10:21pm.

If the digits of a number may be any one of 0 through 9 (except the first digit cannot be zero), and the system of alternating signs of coefficients is used to create a polynomial, what is the least number m of real zeros the polynomial can have? What is the greatest number M of real zeros it may have? Can a polynomial of this type have any whole number of real zeros between m and M? Why or why not?

## Answer This Question

## Related Questions

- math - If the digits of a number may be any one of 0 through 9 (except the first...
- math - If the digits of a number may be any one of 0 through 9 (except the first...
- Math - It's a riddle question. All six digits in the number even remember that ...
- Math - It's a riddle question. All six digits in the number even remember that ...
- math-probability - A state lottery has a daily drawing to form a four-digit ...
- math - Find a six-digit even number containing no zeros and no repeating digits ...
- math,correction, bobpursly - Since when is 5^7 =8125? if a number is a multple ...
- math - Any of the ten digits 0 through 9 may be used in a 6-digit code, but no ...
- math - Using the numbers 1 through 9 with no repeats, find a 9 number such that...
- math - I am thinking of a two-digit number in which the sum of the digits is 9 ...

More Related Questions