Saturday

December 20, 2014

December 20, 2014

Posted by **Kate** on Sunday, February 10, 2013 at 7:20pm.

Y=((sin3theta)(tan3theta))^12

- Calculus -
**Steve**, Sunday, February 10, 2013 at 7:31pmy = (sin3θ tan3θ)^12

y' = 12(sin3θ tan3θ)^11 (3cos3θtan3θ + 3sin3θsec^2 3θ)

= 108(sin3θtan3θ)^11(sin3θ+sin3θ(1+tan^2 3θ))

= 108(sin3θtan3θ)^11 (2sin3θ + sin3θtan^2 3θ)

or other ways

or, expanding first,

y = sin^12 3θ * tan^12 3θ

y' = 12sin^11 3θ tan^12 3θ (3cos 3θ) + 12sin^12 3θ tan^11 3θ (3sec^2 3θ)

which I'm sure massages out to the same.

**Answer this Question**

**Related Questions**

maths - show that sin3theta-cos2theta =(1-sin theta)(4sin squared theta + 2sin ...

maths - show that sin3theta-cos2theta =(1-sin theta)(4sin squared theta + 2sin ...

calculus - a billboard 20ft tall is located on top of a building with its lower ...

related rates with work shown - this is a relate rates problem in calculus in a ...

trig math - Prove that tan(theta)tan(60+theta)=tan3theta

Calculus - Determine the intervals on which the function is concave up and ...

Calculus - I wanted to confirm that I solved these problems correctly (we had to...

calculus - the equation V=U^5=7sqrtW-WZ relates the variables, V,U,W,Z. ...

calculus - Differentiate with respect to x (3x^2-5ax+a^2)^4

Calculus :( - Differentiate with respect to (t). y = d cos(t) + (t^2)sin(t)