Posted by **Wes** on Sunday, February 10, 2013 at 7:00pm.

A rock is dropped from a treetop 19.6 m high, and then,

1.00 s later, a second rock is thrown down. With what

initial velocity must the second rock be thrown if it is to

reach the ground at the same time as the first?

I'm not sure how to find the initial velocity of the thrown rock, since it's not 0

What I have so far:

1st rock:

Yo=o

Yf=19.6 m

Vo=o

Vf=

T=

A= -9.80 m/s^2

I think I've found the final velocity and time of the 1st rock

(Vf^2=Vo^2-2g(Y-Yo)

or final velocity squared = initial velocity(0 m/s)^2 -2(9.80)(-19.6-0)

which is = to -19.6 m/s

Time = 2 seconds

(Vf=Vo-gt, Vf/Vo-g=T, -19.6 m/s /-9.80 m/s^2, 2 seconds

How do I find the initial velocity of a throw object when I know:

Yo=o

Yf=19.6 m

T= 2-1 = 1 second

A- /9.80 m/s^2

Thanks!

- physics -
**Denn**, Tuesday, February 12, 2013 at 6:56am
Wess, there are 2 cases in this prob:

Case 1

U nid to find how long the first rock took to hit the ground: use the formular- s=ut+0.5gt^2 where s=19.6m, u=0, t=?

I gor t=1.97s

Case 2

The second rock took 1.97s-1s to hit the grnd, use same formula & find u

- physics -
**Wes**, Wednesday, February 13, 2013 at 3:40pm
Thank you very much!

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