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April 18, 2014

Homework Help: chemistry

Posted by Fai on Sunday, February 10, 2013 at 6:43pm.

A definite amount of NH4cl was boiled with 100ml of 0.8N naoh for complete reaction . After the reaction mixture containing excess of naoh was neutralized with 12.5ml of 0.75N NH2so4. Calculate the amount of NH4cl taken.

I want you to explain about
100ml x 0.8N = 80
12.5ml x 0.75 =9.375
80 - 9.375 = 70.625
70.625 x mew This part I do not understand
NH4CL = 53.491

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