Posted by Maile on Sunday, February 10, 2013 at 4:31pm.
The body temperatures of adults are normally distributed with a mean of 98.6 degree F and a standard deviation of 0.60 degree F. If 36 adults are randomly selected, find the probability that their mean body temperature is greater than 98.4 degree F.

Statistics  MathGuru, Sunday, February 10, 2013 at 5:40pm
Use zscores:
z = (98.4  98.6)/(0.60/√36) = ?
Once you calculate the zscore, check a ztable for your probability. (Remember that the problem is asking to find the probability "greater than" 98.4)

Statistics  Jane, Sunday, February 10, 2013 at 5:55pm
2 z=0.0228 10.0228 answer 0.9772

Statistics  Anonymous, Wednesday, March 2, 2016 at 9:48pm
.01765
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