Homework Help: Chemistry

Posted by Robby on Sunday, February 10, 2013 at 12:30pm.

At 900.0K, the equilibrium comstant (kp) for the following reaction is 0.345

2SO2 (g) + O2 (g) yields 2SO3 (g)

At equilibrium the partial pressure of SO2 is 35.0 atm and that of O2 is 15.9 atm. What is the partial pressure of SO3 in atm?

6.20 X 10-4 ( I think it is this one)
192
82.0
40.0

Chemistry - DrBob222, Sunday, February 10, 2013 at 2:46pm
I don't think so.
Why do you think that is the one?
Kp = 0.345 = (p^2)SO3/(p)O2*(p^2)SO2
0.345 = (p^2)SO3 = 15.9*(35.0)^2

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