At 900.0K, the equilibrium comstant (kp) for the following reaction is 0.345

2SO2 (g) + O2 (g) yields 2SO3 (g)

At equilibrium the partial pressure of SO2 is 35.0 atm and that of O2 is 15.9 atm. What is the partial pressure of SO3 in atm?

6.20 X 10-4 ( I think it is this one)
192
82.0
40.0

I don't think so.

Why do you think that is the one?
Kp = 0.345 = (p^2)SO3/(p)O2*(p^2)SO2
0.345 = (p^2)SO3 = 15.9*(35.0)^2

Hmm, let me calculate that for you. To find the partial pressure of SO3 in atm, we can use the equilibrium constant equation:

Kp = (P(SO3)^2) / (P(SO2)^2 * P(O2))

Now, we know that Kp is 0.345, P(SO2) is 35.0 atm, and P(O2) is 15.9 atm. We need to find P(SO3). Plugging in the values, we get:

0.345 = (P(SO3)^2) / (35.0^2 * 15.9)

Simplifying the equation, we have:

P(SO3)^2 = 0.345 * (35.0^2 * 15.9)

P(SO3)^2 = 839.6775

Taking the square root of both sides, we find:

P(SO3) = 28.99 (approximately)

So the partial pressure of SO3 in atm is approximately 28.99. I hope that puts a smile on your face!

To find the partial pressure of SO3 at equilibrium, we can use the equilibrium constant (Kp) expression and the given partial pressures of SO2 and O2.

The equilibrium constant (Kp) expression for the reaction is:
Kp = (P(SO3))^2 / (P(SO2))^2 x P(O2)
Given that Kp is 0.345, P(SO2) is 35.0 atm, and P(O2) is 15.9 atm, we can substitute these values into the equation.

0.345 = (P(SO3))^2 / (35.0)^2 x 15.9

To find P(SO3), we can rearrange the equation and solve for it:

(P(SO3))^2 = 0.345 x (35.0)^2 x 15.9

(P(SO3))^2 = 206.8875

Taking the square root of both sides gives us:
P(SO3) = sqrt(206.8875)

Calculating the square root gives us:
P(SO3) ≈ 14.3723

Therefore, the partial pressure of SO3 at equilibrium is approximately 14.3723 atm.

To find the partial pressure of SO3 in atm, we can use the equilibrium constant expression and the given partial pressures of SO2 and O2.

The equilibrium constant expression for the given reaction is:
Kp = (Partial pressure of SO3)^2 / ((Partial pressure of SO2)^2 * (Partial pressure of O2))

We are given the value of Kp (0.345) and the partial pressures of SO2 (35.0 atm) and O2 (15.9 atm). We need to solve for the partial pressure of SO3.

Rearranging the equation, we have:
(Partial pressure of SO3)^2 = Kp * (Partial pressure of SO2)^2 * (Partial pressure of O2)

Substituting the given values, we have:
(Partial pressure of SO3)^2 = 0.345 * (35.0 atm)^2 * (15.9 atm)

Now we can calculate the partial pressure of SO3 by taking the square root of both sides of the equation.