John has 3 unique coins such that the probability of obtaining a head when the coin is flipped is 1/10, 2/10 and 3/10, respectively. If he flips each of the 3 coins once, the probability that at least 1 heads appears is p. What is the value of 1000p?
look at your prior question, redo the numbers.
To find the probability that at least 1 head appears when flipping each of the 3 coins once, we can use the complement rule. We would find the probability that no heads appear and then subtract that from 1.
The probability of obtaining a tail when flipping the first coin is 9/10 (1 - 1/10). Similarly, the probability of obtaining a tail when flipping the second coin is 8/10 (1 - 2/10), and when flipping the third coin is 7/10 (1 - 3/10).
Since each coin flip is independent, we can multiply these probabilities together to find the probability that no heads appear:
(9/10) * (8/10) * (7/10) = 504/1000 = 0.504
Now, we can subtract this result from 1 to find the probability that at least 1 head appears:
1 - 0.504 = 0.496
To find the value of 1000p, we multiply this probability by 1000:
1000 * 0.496 = 496
Therefore, the value of 1000p is 496.