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December 29, 2014

December 29, 2014

Posted by **Shadow** on Saturday, February 9, 2013 at 9:40pm.

f(x) = f(x-3)+2 if x > 10

-5 if x <= 10

Would the answer be 1? Thanks

- Math -
**Shadow**, Saturday, February 9, 2013 at 10:17pmI believed the answer is 16 but computer teacher is telling me it 1. Thanks

- Math -
**Reiny**, Saturday, February 9, 2013 at 10:53pmwhen x = 17

f(17) = f(14) + 2

but

f(14) = f(11) + 2

but

f(11) =f (8) + 2

but f(8) = -5 , since x ≤ 10

so f(11) = -5+2 = -3

f(14) = -3+2 = -1

f(17) = -1+2 = +1

(strange question)

- Math -
**Shadow**, Saturday, February 9, 2013 at 10:57pmLet say the other function is

x-2 , if x < 0

x^2 + 1 , if x >= 0

f(-4) would be -6? I kind of not understand why do we keep going down the value. Thanks

- Math -
**Reiny**, Saturday, February 9, 2013 at 11:18pmIn this last example your function is well defined as

f(x) = x-2 or x<0 and f(x) = x^2 + 1 for x≥0

so f(-4) simply falls in the first part

f(x) = x-2

f(-4) = -4 - 2 = -6 , so you are right.

Your first problem did not have f(x) defined explicitly.

It was defined in terms of f(x-3)

so we had to find values step-by-step

- Math -
**Shadow**, Saturday, February 9, 2013 at 11:38pmOh, thanks you so much! I did not realize f(x-3) and (x-3) make such different.

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