Posted by Shadow on Saturday, February 9, 2013 at 9:40pm.
Solve the piece wise function when f(17)
f(x) = f(x3)+2 if x > 10
5 if x <= 10
Would the answer be 1? Thanks

Math  Shadow, Saturday, February 9, 2013 at 10:17pm
I believed the answer is 16 but computer teacher is telling me it 1. Thanks

Math  Reiny, Saturday, February 9, 2013 at 10:53pm
when x = 17
f(17) = f(14) + 2
but
f(14) = f(11) + 2
but
f(11) =f (8) + 2
but f(8) = 5 , since x ≤ 10
so f(11) = 5+2 = 3
f(14) = 3+2 = 1
f(17) = 1+2 = +1
(strange question)

Math  Shadow, Saturday, February 9, 2013 at 10:57pm
Let say the other function is
x2 , if x < 0
x^2 + 1 , if x >= 0
f(4) would be 6? I kind of not understand why do we keep going down the value. Thanks

Math  Reiny, Saturday, February 9, 2013 at 11:18pm
In this last example your function is well defined as
f(x) = x2 or x<0 and f(x) = x^2 + 1 for x≥0
so f(4) simply falls in the first part
f(x) = x2
f(4) = 4  2 = 6 , so you are right.
Your first problem did not have f(x) defined explicitly.
It was defined in terms of f(x3)
so we had to find values stepbystep

Math  Shadow, Saturday, February 9, 2013 at 11:38pm
Oh, thanks you so much! I did not realize f(x3) and (x3) make such different.
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