Math
posted by Shadow on .
Solve the piece wise function when f(17)
f(x) = f(x3)+2 if x > 10
5 if x <= 10
Would the answer be 1? Thanks

I believed the answer is 16 but computer teacher is telling me it 1. Thanks

when x = 17
f(17) = f(14) + 2
but
f(14) = f(11) + 2
but
f(11) =f (8) + 2
but f(8) = 5 , since x ≤ 10
so f(11) = 5+2 = 3
f(14) = 3+2 = 1
f(17) = 1+2 = +1
(strange question) 
Let say the other function is
x2 , if x < 0
x^2 + 1 , if x >= 0
f(4) would be 6? I kind of not understand why do we keep going down the value. Thanks 
In this last example your function is well defined as
f(x) = x2 or x<0 and f(x) = x^2 + 1 for x≥0
so f(4) simply falls in the first part
f(x) = x2
f(4) = 4  2 = 6 , so you are right.
Your first problem did not have f(x) defined explicitly.
It was defined in terms of f(x3)
so we had to find values stepbystep 
Oh, thanks you so much! I did not realize f(x3) and (x3) make such different.