Posted by **god** on Saturday, February 9, 2013 at 6:35pm.

A particle revolves in a horizontal circle of radius 3.20 m. At a particular instant, its

acceleration is 1.20 m/s

2

in a direction that makes an angle of 55.0ยบ to its direction of motion.

Determine its speed (a) at this moment, and (b) 1.50 s later, assuming constant magnitude of

tangential acceleration.

- physics -
**bobpursley**, Saturday, February 9, 2013 at 6:51pm
I am not certain how the 55 degrees is measured? Is it in the plane of revolution? towards inside, or outside?

- physics -
**god**, Sunday, February 10, 2013 at 12:00pm
55 from the tangent, so i think its accelerating.

- physics -
**Samuel You**, Wednesday, December 14, 2016 at 9:48pm
Centripetal acceleration equals tangent 55 times 1.05. Obtain the velocity at that point with that. V=Vinitial+at, where a is the anet in the direction of motion. Therefore, get the original velocity, find the anet through a cosine with the tangent acceleration, and solve the kinematics equation.

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