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calculate the number of g fes04 that will be oxidized by 24ml of a 250N Kmn04 in a solution acidified with sulfuric acid. The unbalanced equation for the reaction.

The answer 0.912g

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  • chemistry - ,

    mL x N = # milliequivalents KMnO4.
    # m.e. KMnO4 = # m.e. FeSO4
    # m.e. FeSO4 x equivalent weight FeSO4 = g FeSO4.
    All of that can be put together to make one nice equation.
    mL x N x m.e.w. = grams.
    24 x 0.250 x 0.152 = 0.0912g FeSO4.

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