Thursday

August 21, 2014

August 21, 2014

Posted by **Anonymous** on Saturday, February 9, 2013 at 1:00pm.

(bc'+a'd)(ab'+cd')-Simplify

My best guess is to use the distributive

property.

(a+b)(a+c)= a(b+c). But now that there is a 4th variable what do I do?

- Boolean Algebra -
**Steve**, Saturday, February 9, 2013 at 2:23pmuse it twice

(bc'+a'd)(ab'+cd')

= bc'(ab'+cd') + a'd(ab'+cd')

= abb'c' + bcc'd' + aa'b'd + a'cdd'

Now, since xx' = 0, the result is 0

- Boolean Algebra -
**Anonymous**, Sunday, February 10, 2013 at 1:01amOOK, thank you, I see how you did that step. that makes perfect sense.

so simplified you get

ac'+bd'+b'd+a'c

- Boolean Algebra -
**Steve**, Sunday, February 10, 2013 at 6:54pmno, the result is 0, since

abb'c = a(bb')c = a0c = 0

each term is 0

**Related Questions**

Distributive property - How would I multiply these expression? 6(h-4) -3(x+8) -...

Boolean algebra - Simplify this function using Boolean algebra laws? I am stuck...

math - Write an algebraic expression that requires each of the following ...

algebra 2 - It says to: Use the Distributive Property to show that the following...

Algebra/Distributive Properties - Solve these fraction equations: 2/3 - 8/9 = c/...

Math-Distributive Property - Use the distributive property to simplify: 3(m-1)-(...

Math - okay so i feel like a dummie for not knowing this but i need the answer ...

Algebra 1 - Use the power of a product property to simplify the expression. (2)^...

Algebra - 28. Use the Distributive Property to simplify x(4x^2 + x + 4) Is it 4x...

algebra - y=3(x+5)(x-2) I'm suppose to simplify right? There is no way to solve ...