Posted by Anonymous on Saturday, February 9, 2013 at 8:16am.
if p(x) = px^7 + qx^3 + rx  5
where p , q , r are constants ,
if p(7) = 7 then p(7) = ?

mathsurgently needed  Steve, Saturday, February 9, 2013 at 2:47pm
p(x) = (px^7+qx^3+rx)  5
p(x) = (px^7+qx^3+rx)  5
p(x) + 5 = (p(x)+5)
p(7) + 5 = p(7)  5
p(7) = 7  10
p(7) = 3