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Posted by on Saturday, February 9, 2013 at 8:16am.

if p(x) = px^7 + qx^3 + rx - 5
where p , q , r are constants ,
if p(-7) = 7 then p(7) = ?

  • maths-urgently needed - , Saturday, February 9, 2013 at 2:47pm

    p(x) = (px^7+qx^3+rx) - 5
    p(-x) = -(px^7+qx^3+rx) - 5

    p(-x) + 5 = -(p(x)+5)
    p(-7) + 5 = -p(7) - 5
    p(-7) = 7 - 10
    p(-7) = -3

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