Saturday

April 19, 2014

April 19, 2014

Posted by **karen** on Saturday, February 9, 2013 at 6:52am.

- math -
**JJ**, Saturday, February 9, 2013 at 1:00pmIf it is okay to have blue green red and red green blue as a different flag...then you will have 60 possible flags. For the first stripe you have 5 choices, for the second 4 choices and for the last 3 choices = 60 flags.

If you cannot have the same colors in a different order than you will have only 10 possibilities. Use the Combination rule of 5 factorial divided by (3 factorial times 3 factorial). 5 factorial means 5X4X3X2X1 =120 divided by (3x2x1)(2x1) so you have 120/12 = 10.

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