Posted by
**Tonya** on
.

During the second round of the 1989 U.S. Open golf tournament, four golfers scored a hole in one on the sixth hole. The odds of a professional golfer making a hole in one are estimated to be 3,708 to 1, so the probability is 1/3,709. There were 155 golfers participating in the second round that day.

Estimate the probability that four golfers would score a hole in one on the sixth hole. Use the poisson approximation to the binomial. (Round the mean value to 3 decimal places and round your final answer to 9 decimal places.)