Posted by **Ashley** on Friday, February 8, 2013 at 6:00pm.

A person who weighs 506 N is riding a 94-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 6.70 x 105 Pa, what is the area of contact between each tire and the ground?

- Physics -
**drwls**, Saturday, February 9, 2013 at 8:52am
(total Contact area)x(Gauge pressure)

= 2*(single tire Contact Area)x6.70*10^5 N/m^2

= Total wt.

= 600 N

Contact area = 4.48*10^-4 m^2

= 4.48 cm^2

- Physics -
**Name**, Sunday, June 23, 2013 at 4:46am
P = F/A

But there are two tires. So the weight will be supported by the two tires, thus two areas.

So P=F/2A, solving this,

A = F/2P

A = 600/2*6.7*10^5

## Answer this Question

## Related Questions

- physics - A person who weighs 717 N is riding a 80-N mountain bike. Suppose the ...
- physics 1 - A person who weighs 869 N is riding a 98-N mountain bike. Suppose ...
- physics - A person who weighs 691 N is riding a 89-N mountain bike. Suppose the ...
- Physics please check - A person who weighs 655 N is riding a 98 N mountain bike...
- Physics - Suppose that when you ride on your 7.90-kg bike the weight of you and ...
- physics - Assuming bicycle tires are perfectly flexible and support the weight ...
- physics - A 66.0 kg rider sitting on a 7.1 kg bike is riding along at 9.4 m/s in...
- Physics - Jack rides his 213kg motor cross bike 25.3m up a 30.0 degree slope at ...
- Physics - Hey can someone help, im having trouble converting alot. IP The weight...
- physics - You are riding your bike and the tire has a radius of 0.33 m and mass ...

More Related Questions