Thursday

April 24, 2014

April 24, 2014

Posted by **Ashley** on Friday, February 8, 2013 at 6:00pm.

- Physics -
**drwls**, Saturday, February 9, 2013 at 8:52am(total Contact area)x(Gauge pressure)

= 2*(single tire Contact Area)x6.70*10^5 N/m^2

= Total wt.

= 600 N

Contact area = 4.48*10^-4 m^2

= 4.48 cm^2

- Physics -
**Name**, Sunday, June 23, 2013 at 4:46amP = F/A

But there are two tires. So the weight will be supported by the two tires, thus two areas.

So P=F/2A, solving this,

A = F/2P

A = 600/2*6.7*10^5

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