Posted by **Ashley** on Friday, February 8, 2013 at 6:00pm.

A person who weighs 506 N is riding a 94-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 6.70 x 105 Pa, what is the area of contact between each tire and the ground?

- Physics -
**drwls**, Saturday, February 9, 2013 at 8:52am
(total Contact area)x(Gauge pressure)

= 2*(single tire Contact Area)x6.70*10^5 N/m^2

= Total wt.

= 600 N

Contact area = 4.48*10^-4 m^2

= 4.48 cm^2

- Physics -
**Name**, Sunday, June 23, 2013 at 4:46am
P = F/A

But there are two tires. So the weight will be supported by the two tires, thus two areas.

So P=F/2A, solving this,

A = F/2P

A = 600/2*6.7*10^5

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