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A person who weighs 506 N is riding a 94-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 6.70 x 105 Pa, what is the area of contact between each tire and the ground?

  • Physics -

    (total Contact area)x(Gauge pressure)
    = 2*(single tire Contact Area)x6.70*10^5 N/m^2
    = Total wt.
    = 600 N

    Contact area = 4.48*10^-4 m^2
    = 4.48 cm^2

  • Physics -

    P = F/A
    But there are two tires. So the weight will be supported by the two tires, thus two areas.

    So P=F/2A, solving this,

    A = F/2P

    A = 600/2*6.7*10^5

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